00:01
Hello, students.
00:02
So in this question, you are given with the table where the number of electron groups are given to you.
00:07
The bond angle has been asked.
00:10
I have named this blank of av, cd, okay, up to where.
00:13
And then you are given with the outer atoms or the loan pairs and the number of outer atoms or the loan pairs given.
00:20
Right, and then you have been asked about the shape of some of these.
00:23
Okay, so i have also named this as one, two, three.
00:26
So let's get started.
00:28
So for the first one, if we see, we are given.
00:31
With the electron group of 2 is all right electron group of 2 is given and the outer element they have given as 2 so in this how we can say what will be the bond angle so suppose you take it with the example of carbon and carbon and oxygen they are having the triple bond all right so here if you see what will be the angle between this what will be the bond angle this angle is 180 degrees okay it is a straight angle so it is 180 degrees so you can write your a is we can write a is 180 degrees and one and one is what one is the shape okay and the shape over here is the linear shape okay it is in the line form we can say it is in the linear shape so next one we have been asked about the number of electron group three and b we have to take off 3 by 0 means 3 we have the outer electron and 0 loan 1.
01:38
So i'm taking the example of bf 3, df 3.
01:44
All right.
01:44
And here if you see, this bond angle is 120 degrees.
01:48
So you can write it over here that here we have a is equal to 120 degrees and the shape is already mentioned that is triangular planar.
01:56
Now the next one we have of two side atoms, two outer atoms and one lone pair.
02:03
Okay so in the two side atoms in one lone pair we have nitrogen dioxide nitrogen and we have here double bond o and here single one okay and here on the nitrogen we have a loan pair all right so here if you see the angle will be in this case the angle this angle this angle will be less than 90 degree so you can say less than 90 degrees and here you are probably this wasn't a resource you can make this correct okay this was b all right so now c is equal to this is 120 degrees or this one is less than 90 degrees so here we have to tell us the shape also so 2 is equal to bent or v shape bent or v shape all right so now we have now we have to find out for the 4 right so the first part we have is where the 4 are the automost atoms and zero known pure.
03:14
For this, we can say we have carbon with all hydrogen, same methane example...