Use the Squeeze Theorem to show that: $\lim_{x \to 0} \sqrt{x^3 + x^2 \cos(\frac{2\pi}{3x})} = 0$.
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The Squeeze Theorem states that if f(x) ≤ g(x) ≤ h(x) for all x in some interval containing c, except possibly at c itself, and if lim f(x) as x approaches c equals lim h(x) as x approaches c equals L, then lim g(x) as x approaches c also equals L. Show more…
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