Use the acidity model $\mathbf{p} \mathbf{H}=-\log \left[\mathbf{H}^{+}\right],$ where acidity $(\mathbf{p} \mathbf{H})$ is a measure of the hydrogen ion concentration [$\left.\mathbf{H}^{+}\right]$ (measured in moles of hydrogen per liter) of a solution. Compute $\left[\mathrm{H}^{+}\right]$ for a solution in which $\mathrm{pH}=3.2$.
Added by M-Nica H.
Step 1
First, we need to rearrange the acidity model to solve for $\left[\mathrm{H}^{+}ight]$: $$\mathbf{p} \mathbf{H}=-\log \left[\mathbf{H}^{+}ight] \right]$$ $$\left[\mathbf{H}^{+}ight] = 10^{-\mathbf{p} \mathbf{H}}$$ Show moreβ¦
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Use the acidity model $\mathbf{p} \mathbf{H}=-\log \left[\mathbf{H}^{+}\right],$ where acidity $(\mathbf{p} \mathbf{H})$ is a measure of the hydrogen ion concentration [$\left.\mathbf{H}^{+}\right]$ (measured in moles of hydrogen per liter) of a solution. Compute $\left[\mathrm{H}^{+}\right]$ for a solution in which $\mathrm{pH}=5.8$.
Use the acidity model $\mathbf{p H}=-\log \left[\mathbf{H}^{+}\right]$ where acidity (pH) is a measure of the hydrogen ion concentration $\left[\mathbf{H}^{+}\right]$ (in moles of hydrogen per liter) of a solution. Compute $\left[\mathrm{H}^{+}\right]$ for a solution for which $\mathrm{pH}=5.8$
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