Two consecutive positive numbers are such that the sum of their squares is 13. Find the two numbers.
Added by Joseph G.
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According to the given information, the sum of their squares is 13. So we can write the equation: x^2 + (x+1)^2 = 13 Expanding the equation: x^2 + (x^2 + 2x + 1) = 13 Combining like terms: 2x^2 + 2x + 1 = 13 Subtracting 13 from both sides: 2x^2 + 2x - 12 = Show more…
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