2. Evaluate $\int_{-1}^{2} \int_{-2y}^{2y^2} 10(2x - 3y)dxdy$
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To do this, we need to integrate with respect to x first, treating y as a constant. ∫10(21 - 3y) dxdy = ∫10(21 - 3y) dx dy = 10 ∫(21 - 3y) dx dy = 10 [21x - 3yx] dy = 10 [21x - 3yx] |y=0 to y=2 = 10 [(21x - 6x) |y=0 to y=2] = 10 [(21x - 6x) |y=0 to Show more…
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