00:01
All right, guys, let's solve this question.
00:04
The amount of energy spent in the given simple payback period can be expressed as following.
00:11
That is, e, t, o, t, is equal to e multiplied by spp.
00:31
The mass difference is obtained from the heating value.
00:35
The total energy spent and the given efficiencies.
00:41
So delta m is equal to m -coal minus m -i -g -g -c -c.
00:56
So we have e total divided by q -h -v, multiplied by one eta of coal minus 1 divided by eta i gcc c okay now we further solve it and it's e point s p p divided by qhv multiplied by 1 over eta of coal minus 1 over eta of igcc.
02:03
Okay guys the amount of money saved using the igcc is expressed as following delta m is equal to m -i -g -cc minus m -kohl into e.
02:29
The unit cost is determined from the money saved and the mass difference in the two cases...