The series ∑k=4^∞(k^2)/((k+1)(k+2))

Name: The series ∑k=4^∞(k^2)/((k+1)(k+2))
Uploaded: 2023-06-11T16:12:16-08:00
Duration: 1 min 38 s
Channel: Numerade
Description: The series ∑k=4^∞(k^2)/((k+1)(k+2))

Question

Hunny Aggarwal · Answer

Here the nth term is tn is equal to n minus 1 summation divided by n factorial. So this is equal

Nick Johnson · Answer

So our given series here is, well, 1 over 1, and then plus 1 over 1 plus 2, plus 1 plus 2, plus

Akash Goyal · Answer

students we have given a series like just one plus one plus two three four three into four up to

Hunny Aggarwal · Answer

Here the nth term tn is denoted by 1 plus 2 plus 3 plus up to up to n divided by n factorial. So

Hunny Aggarwal · Answer

The solution for this will be tn is equal to 2n by 2n minus 1 factorial. So this can be written

Question

The series \(\sum_{k=4}^{\infty} \frac{k^2}{(k+1)(k+2)}\)

Please give Ace some feedback