Use Newton-Raphson method to find the root of the following equation, starting from an initial guess $x_0 = 4.45302$: $e^{-0.6(2x - 9.8956)^2} - 1 = 0$ The relative error is defined by $\epsilon_a = \left| \frac{x_{i+1} - x_i}{x_{i+1}} \right|$. Obtain the root with the relative error less than $10^{-6}$. Enter your answer below: $x = $
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The relative error is a measure of how much the approximation of a value differs from the true value, expressed as a percentage or a ratio. Show more…
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