Question

13. The product $\sqrt[3]{2} \cdot (\sqrt[3]{2})^{-1} \cdot \sqrt[3]{32}$ equals: a) $\sqrt[3]{32}$ b) c) $\sqrt{2}$ d) 2

          13. The product $\sqrt[3]{2} \cdot (\sqrt[3]{2})^{-1} \cdot \sqrt[3]{32}$ equals:
a) $\sqrt[3]{32}$
b) 
c) $\sqrt{2}$
d) 2

13. The product √(2)· (√(2))^-1·√(32) equals:
a) √(32)
b)
c) √(2)
d) 2

Added by Morgan W.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Derrick Danso

Step 1

We can rewrite 12√32 as 12 * √(2^5). Since the square root of 2^2 is 2, we can simplify this further to 12 * 2 * √(2^3) = 24√8. Now, we can rewrite the expression as: 6√2 - 1/3 * 24√8 Show more…

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The product 3âˆš2(2) - 1/3 * 12âˆš32 equals-

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Question

13. The product $\sqrt[3]{2} \cdot (\sqrt[3]{2})^{-1} \cdot \sqrt[3]{32}$ equals: a) $\sqrt[3]{32}$ b) c) $\sqrt{2}$ d) 2

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