The average value of the function f(t) = -2te^-t^2 for the interval [0,8] is 0.346.
Added by Matthew B.
Step 1
Step 1: To find the average value of the function f(t) over the interval [0,8], we use the formula: \[ \text{Average value} = \frac{1}{b-a} \int_{a}^{b} f(t) \, dt \] where a and b are the limits of the interval. Show more…
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