Test whether the function is even, odd, or neither even nor odd. f(x) = 10x^2 + 1
Added by Brian M.
Step 1
Even function: A function is even if f(-x) = f(x) for all x in the domain. f(-x) = 10(-x)^2 + 1 = 10x^2 + 1 = f(x) Therefore, f(x) is an even function. Show more…
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