Find \lim_{t \to 0} \frac{\tan 6t}{\sin 3t}
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Taking the derivative of both the numerator and denominator, we get: lim (cos 3t) / 0 This is still an indeterminate form, so we need to use L'Hopital's rule again. Taking the derivative of the numerator, we get: lim (-3 sin 3t) / 0 This is now a form of 0/0, Show more…
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