T/4 sec2 X dx (1 + 7tan x)2/3
Added by Patricia G.
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Step 1
Let $u = 1 + 7\tan{x}$. Then, the derivative of $u$ with respect to $x$ is: $$\frac{du}{dx} = 7\sec^2{x}$$ Now, we can rewrite the integral in terms of $u$: $$\int \frac{T}{4} \sec^2{x} (1 + 7\tan{x})^{\frac{2}{3}} dx = \int \frac{T}{4} \cdot \frac{1}{7} Show more…
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