18. $\lim_{x \to 2^{-}} \frac{x^2 - 2x}{x^2 - 4x + 4}$
Added by Angela M.
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Step 1
We can do this by plugging in 2 for x and simplifying: lim x→2 (2x^2 - 4x + 4)/(x - 2) = lim x→2 [(2x - 4)(x - 1)]/(x - 2) = lim x→2 (2x - 4)(x - 1) = (2(2) - 4)(2 - 1) = 0 Show more…
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