t2 16 lim (7-4 ~2t2 3t + 20
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So we set the denominator equal to zero and solve for t: 2t^2 + 3t + 20 = 0 Using the quadratic formula, we get: t = (-3 ± sqrt(3^2 - 4(2)(20))) / (2(2)) t = (-3 ± sqrt(-151)) / 4 Since the square root of a negative number is not a real number, this expression Show more…
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