Question

f(t) = \begin{cases} 0, & t < 2 \\ t - \pi, & \pi \le t < 2\pi \\ 0, & t \ge 2\pi \end{cases}

          f(t) = \begin{cases} 0, & t < 2 \\ t - \pi, & \pi \le t < 2\pi \\ 0, & t \ge 2\pi \end{cases}

f(t) = 0, t < 2
t - π, π≤t < 2π
0, t ≥2π

Added by Kayla B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Donna Densmore

Step 1

Subtract $t$ from both sides: $0 < t + 2 ZT$ Now, factor out $t$: $0 < t(1 + 2Z)$ Since we don't know the sign of $(1 + 2Z)$, we cannot divide by it to solve for $t$. However, we can consider two cases: 1) If $(1 + 2Z) > 0$, then $t > 0$. 2) If $(1 + 2Z) < Show more…

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