6) y = ln[(√(x^2 - 5x - 1)tan^4(3x))/((x^3 + x - 1)^10)]

Name: 6) y = ln[(√(x^2 - 5x - 1)tan^4(3x))/((x^3 + x - 1)^10)]
Uploaded: 2023-04-12T10:55:32-08:00
Duration: 1 min 21 s
Channel: Numerade
Description: 6) y = ln[(√(x^2 - 5x - 1)tan^4(3x))/((x^3 + x - 1)^10)]

Question

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Question

6) $y = \ln\left[\frac{\sqrt{x^2 - 5x - 1} \tan^4(3x)}{(x^3 + x - 1)^{10}}\right]$

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