(b) $\lim_{x \to \infty} \frac{5x^3 - 2x^2 + 1}{1 - 3x}$
Added by Kristi M.
Close
Step 1
The "~" symbol typically represents "approximately equal to," so we can rewrite the expression as Sx' ≈ 2x^2 + 1 (mod 6). Show more…
Show all steps
Your feedback will help us improve your experience
Kyle Sower and 55 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
lim x->1 x^2 / (x + 2) = 1/3
Ben B.
lim x→-1 (2x^2 + 3x + 1) / (x^2 - 2x - 3)
Madhur L.
lim x->2+ (3x - 11) / (2x^2 - 9x + 10)
Adi S.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD