Solve $(1 + x^2)y'' - 2xy' = 0$ given that $y_1 = 1$ is a solution.
Added by Tiffany M.
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Step 1
First, let's differentiate the equation with respect to x to find the derivative of y: d/dx(1 + xy - 2xy') = 0 Differentiating each term separately, we get: 0 + x(dy/dx) - 2y - 2xy' = 0 Show more…
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