Solve y'' = 206(t^3), y(0) = 1, y'(0) = 0
Added by Joshua P.
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To do this, we can integrate twice: y' = ∫ 206(t^3) dt = 51.5t^4 + C1 y = ∫ (51.5t^4 + C1) dt = 10.3t^5 + C1t + C2 Show more…
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