Solve using Laplace Transform. \(y' - y = 2\cos(5t), \quad y(0) = 0\)
Added by Ryan M.
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First, let's take the Laplace transform of both sides of the equation: L{Y'} - L{Y} = L{Zcos(St)} Using the property of the Laplace transform for derivatives, we have: sY(s) - Y(0) - Y(s) = L{Zcos(St)} Since Y(0) = 0, the equation simplifies to: sY(s) - Y(s) = Show more…
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