Solve $\triangle A B C$ $\beta=25^{\circ}, \quad \gamma=41^{\circ}, \quad b=170$
Added by Felipe N.
Step 1
Use the fact that the sum of angles in a triangle is 180 degrees to find the measure of angle A: $$\alpha = 180^\circ - \beta - \gamma = 180^\circ - 25^\circ - 41^\circ = 114^\circ$$ Show more…
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