Solve the system using elementary operations. 2x + 3y - z = 3 x + 2y + z = 2 2x + 3y + 3z = -3 (x, y, z) = (\boxed{\hspace{0.5cm}}, \boxed{\hspace{0.5cm}}, \boxed{\hspace{0.5cm}})
Added by Christine G.
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Step 1: Rearrange the equation to have all terms on one side: 23yz^3 + 2y + z^2 - 2 - 3y^3z^3 = 0 Show more…
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