Solve the recurrence: T(n) = 3T(n/3) + 1 T(1) = 2
Added by Benjamin P.
Step 1
.. = 3^k T(n/3^k) + 1 + 3 + 3^2 + ... + 3^(k-1) We can see that the pattern is a geometric series with a common ratio of 3. Therefore, the sum of the series is: 1 + 3 + 3^2 + ... + 3^(k-1) = (3^k - 1) / 2 Substituting this back into the original equation, we Show more…
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