Solve the initial value problem $y' + 4y = 8u_2(t)$, $y(0) = 6$ (12 points)
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Step 1
The characteristic equation is r + 4 = 0, which has the solution r = -4. Therefore, the homogeneous solution is y_h(t) = c1e^(-4t), where c1 is a constant. Show more…
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