Solve the initial value problem: (x+2y)dx+(2yx - cos y)dy = 0, y(1) = T
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To do this, we check if the partial derivative of the coefficient of dx with respect to y is equal to the partial derivative of the coefficient of dy with respect to x. ∂(x+2y)/∂y = 2 ∂(2yx - cos y)/∂x = 2y Since the partial derivatives are not equal, the Show more…
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