Solve the initial value problem. $\frac{d y}{d t}=\sqrt{t}, \quad y(1)=1$
Added by Stephanie C.
Step 1
To do this, we can integrate both sides with respect to $t$: $$\int \frac{dy}{dt} dt = \int \sqrt{t} dt$$ $$y = \frac{2}{3}t^{\frac{3}{2}} + C$$ where $C$ is a constant of integration. Show more…
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