Solve the initial value problem dy dx (8x2 + 2) (4x 3), Y(2) = 7 y(x)
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Step 1
First, we need to find the antiderivative of (8x^2 + 2) (4x^3), which can be done by using the distributive property and the power rule of integration: ∫(8x^2 + 2) (4x^3) dx = ∫(32x^5 + 8x^3) dx = 32/6 x^6 + 8/4 x^4 + C where C is the constant of integration. Show more…
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