Solve the initial value problem dy = 9sin(t) + 1, %(3) dx^2. NOTE: Enter the exact answer: y(t)
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Step 1
To do this, we integrate both sides with respect to t: ∫dy = ∫(9sin(t) + 1)dx y = -9cos(t) + x + C where C is the constant of integration. Show more…
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