Solve the initial value problem.\\ $\frac{dy}{dt} + 4y = 11, y(0) = 1$\ The solution is $y = $
Added by Joseph S.
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To do this, we can use an integrating factor. The integrating factor is e^(4t), so we multiply both sides of the equation by e^(4t): e^(4t)dy + 4e^(4t)y = 11e^(4t) Now we can recognize the left side as the product rule for the derivative of e^(4t)y: d/dt Show more…
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