"Solve the given initial value problem. 26 -9 x(t), x(0) 8 9 -41 x' (t) = 36 x(t)"
Added by Patricia H.
Step 1
The integrating factor is given by: IF(t) = e^(∫(-36/41)dt) = e^(-36t/41) Multiplying both sides of the differential equation by the integrating factor, we get: e^(-36t/41)x'(t) + (36/41)e^(-36t/41)x(t) = (26/41)e^(-36t/41) Now, we can integrate both sides Show more…
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