The dot product of two vectors $\vec{A}$ and $\vec{B}$ is given by:
$\vec{A} \cdot \vec{B} = |\vec{A}| |\vec{B}| \cos(\theta)$
where $\theta$ is the angle between the two vectors.
In this case, $\theta = 90^\circ$, so $\cos(90^\circ) = 0$.
Therefore, $\vec{A}
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