Solve the following equation for 0° ≤ θ ≤ 360°: sin(θ + 15°) = √2/2.
Added by Charles S.
Step 1
First, we need to isolate the angle (θ + 15°) by subtracting 15° from both sides of the equation: sin θ = (√2)/2 - sin 15° Show more…
Show all steps
Close
Your feedback will help us improve your experience
Elizabeth Waters and 74 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve the given trigonometric equation on $0^{\circ} \leq \theta<360^{\circ}$ and express the answer in degrees to two decimal places. $$15 \sin ^{2}(2 \theta)+\sin (2 \theta)-2=0$$
Analytic Trigonometry
Trigonometric Equations
Solve the given trigonometric equation on $0^{\circ} \leq \theta<360^{\circ}$ and express the answer in degrees rounded to two decimal places. $$15 \sin ^{2}(2 \theta)+\sin (2 \theta)-2=0$$
Solve the given trigonometric equation on $0^{\circ} \leq \theta<360^{\circ}$ and express the answer in degrees to two decimal places. $$ 15 \sin ^{2}(2 \theta)+\sin (2 \theta)-2=0 $$
TRIGONOMETRIC EQUATIONS
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Watch the video solution with this free unlock.
EMAIL
PASSWORD