Solve the differential equation with initial condition $y(0) = 2$ $y' + 4y = e^{3x}y^2$
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Step 1
The characteristic equation is r^2 + 4r + 4 = 0, which has a double root of -2. Therefore, the general solution is y(z) = (c1 + c2z)e^(-2z) + (1/9)e^(3z). Show more…
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