Solve the Bernoulli equation. $xy' + y = y^{-2}$, $x > 0$
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A Bernoulli equation is of the form: y' + p(x)y = q(x)y^n where n is a constant. In our equation, we have: -2xy' + y = yx We can rewrite this as: y' - (1/x)y = (1/(-2x))y^2 So, we have p(x) = -1/x and q(x) = (1/(-2x))y^2, which means n = 2. Show more…
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