Solve $e^x(x+1)dx = (ye^y - xe^x)dy = 0$
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To solve this equation, we can use the substitution y = vx, where v is a new variable. Then, we can rewrite the equation as: ex(x + 1)dx = (vevxex - xex)dx Simplifying this expression, we get: ex(x + 1)dx = ex(vex - x)dx Now, we can divide both sides by ex(x Show more…
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