Solve exactly.\\ $\log_8\left(\frac{8x+8}{2x}\right) = \frac{1}{3}$\\ x = DNE
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Using the logarithmic property loga (mn) = loga m + loga n, we can rewrite the expression as: log8 2x 3 x = log8 2x + log8 3 x Show more…
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