Solve each triangle. $$C=45.6^{\circ}, b=8.94 \mathrm{m}, a=7.23 \mathrm{m}$$
Added by Patrick C.
Step 1
$$\frac{a}{\sin A} = \frac{b}{\sin B}$$ $$\frac{7.23}{\sin A} = \frac{8.94}{\sin 45.6^{\circ}}$$ $$\sin A = \frac{7.23 \cdot \sin 45.6^{\circ}}{8.94}$$ $$A = \arcsin\left(\frac{7.23 \cdot \sin 45.6^{\circ}}{8.94}\right)$$ $$A \approx 36.5^{\circ}$$ Show more…
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