The quadratic formula is:
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
In this case, a = 1, b = $\sqrt{11}$, and c = 3. Substituting these values into the formula, we get:
$$x = \frac{-\sqrt{11} \pm \sqrt{(\sqrt{11})^2 - 4(1)(3)}}{2(1)}$$
Simplifying:
$$x =
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