Solve $(t^2+1)\frac{dy}{dt} = (y^2+1)t$, $y(0) = 0$. Give the solution in explicit form.
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The integrating factor is e^x, so we multiply both sides of the equation by e^x: e^x dy/dx + e^x y = e^x Now we can use the product rule to simplify the left-hand side: d/dx (e^x y) = e^x Integrating both sides with respect to x, we get: e^x y = e^x + Show more…
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