Solve the initial value problem: dy/dx = 2sin(2y), y(-2) = ? The solution is (Type an implicit solution. Type an equation using x and y as the variables)
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Now, we can solve for y by isolating cos(2y): ln|cos(2y)| = -4x - 2C |cos(2y)| = e^(-4x-2C) cos(2y) = ± e^(-4x-2C) Simplifying further: 2y = ± cos^-1(e^(-4x-2C)) y = ± 1/2 cos^-1(e^(-4x-2C)) Show more…
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