sinα= (sinθ)/(√(((h)/(a))^2 + 1 - 2((h)/(a))cosθ))

Name: sinα= (sinθ)/(√(((h)/(a))^2 + 1 - 2((h)/(a))cosθ))
Uploaded: 2023-06-02T03:57:05-08:00
Duration: 53 s
Channel: Numerade
Description: sinα= (sinθ)/(√(((h)/(a))^2 + 1 - 2((h)/(a))cosθ))

Question

Aman Gupta · Answer

In this problem, the given equation can be rewritten as cost 4x can written as cost square of 2x

Aman Gupta · Answer

In this problem, the given equation can be rewritten as sine 4x plus cos 4x into cost 2x by sine

Amrita Bhasin · Answer

This question asks us to prove the identity. We know we can start with the left -hand side, look

Jennifer Stoner · Answer

given 1 minus cosine y times 1 plus cosine y equals f of y squared we are going to simplify this

Aman Gupta · Answer

in this problem the above equation can be rewritten as root 2 sine square of x by 2 minus 1 into

Question

\sin\alpha = \frac{\sin\theta}{\sqrt{(\frac{h}{a})^2 + 1 - 2(\frac{h}{a})\cos\theta}}

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