sin (2) - sin 615)] n= [ln n In(2n + 5)] n=[
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Step 1
First, we need to simplify the expression inside the sine function. We can use the identity sin(a-b) = sin(a)cos(b) - cos(a)sin(b) to rewrite sin(615) as sin(360+255), which gives us: sin(2) - sin(615) = sin(2) - sin(360+255) = sin(2) - [sin(360)cos(255) - Show more…
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