Draw an outer electron box diagram for a Ru 2+ cation.
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Determine the electron configuration of the neutral Ru atom. Ru has an atomic number of 44, so its electron configuration is: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^6\] Show moreā¦
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