: Rewrite the expression in nonradical form without using absolute values for the indicated values of $${1+\cot ^{2} \theta} ; \quad 0<\theta<\pi$$
Added by Donald G.
Step 1
We know that: $$\csc \theta = \frac{1}{\sin \theta}$$ So, we can rewrite the expression as: $$\csc^2 \theta = \left(\frac{1}{\sin \theta}\right)^2 = \frac{1}{\sin^2 \theta}$$ Show more…
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