resolver la ED: y' - 5y = 3e^x - 2x + 1
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The standard form of a linear first-order differential equation is y' + p(x)y = q(x), where p(x) and q(x) are functions of x. To rewrite the given equation in this form, we need to move all the terms to one side of the equation: y' - 5y = 3e^x - 2x + 1 Show more…
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