Read below. 2 void function(Node *head) 3 { 4 5 Node *current = head; 6 Node *prev = NULL, *next = NULL; 7 8 while (current != NULL) { 9 10 next = current->next; 11 current->next = prev; 12 prev = current; 13 current = next; 14 15 } // What is missing here? (one line of code) 1. Explain in a single sentence what the above function performs on a given linked list. 2. Explain in single sentence what the code in line 10 serves to achieve in each loop iteration. 3. Fill in the missing code line in line 14. Your answer
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It is using three pointers: `current`, `prev`, and `next`. The `current` pointer is initially set to the `head` of the linked list. The `prev` pointer is set to `NULL` to indicate the end of the reversed list. The `next` pointer is also set to `NULL` Show more…
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