Question

Question 7 Solve: $|4x + 1| < 8$ $ \frac{-7}{4} < x < \frac{7}{4} $ $ \frac{-9}{4} < x < \frac{7}{4} $ $ x < \frac{7}{4} $ $ \frac{-7}{4} < x < \frac{9}{4} $

          Question 7
Solve: $|4x + 1| < 8$
$ \frac{-7}{4} < x < \frac{7}{4} $
$ \frac{-9}{4} < x < \frac{7}{4} $
$ x < \frac{7}{4} $
$ \frac{-7}{4} < x < \frac{9}{4} $

Question 7
Solve: |4x + 1| < 8
(-7)/(4) < x < (7)/(4)
(-9)/(4) < x < (7)/(4)
x < (7)/(4)
(-7)/(4) < x < (9)/(4)

Added by Aaron C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

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Solved by Expert Jennifer Stoner

Step 1

We are given the inequality $|d^2 + 1| < 8$. Show more…

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Solve: âˆš(d^2 + 1) < 8 âˆš(d^2 + 1) < 8 8 < âˆš(d^2 + 1)

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Question

Question 7 Solve: $|4x + 1| < 8$ $ \frac{-7}{4} < x < \frac{7}{4} $ $ \frac{-9}{4} < x < \frac{7}{4} $ $ x < \frac{7}{4} $ $ \frac{-7}{4} < x < \frac{9}{4} $

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