The density function of random variable X is given as follows: f(x) = (1/8)e^(-6/8x) for x > 6 f(x) = 0 otherwise where x > 0. If E[X] = 11, find ...
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We are given that E[X] = 11, so we can write: E[X] = ∫xf(x)dx where f(x) is the probability density function of X. We can split the integral into two parts, one for x < 6 and one for x ≥ 6: E[X] = ∫6xf(x)dx + ∫∞6f(x)dx For x < 6, f(x) = 0, so the first Show more…
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