Question 3 Solve the initial value problem y" + y = %;y(1) = 0,y(1) = 1
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This is a second-order linear homogeneous differential equation with constant coefficients, so we can assume a solution of the form y = Ae^(rt), where A and r are constants. Substituting this into the equation, we get: r^2 e^(rt) + e^(rt) = 0 Dividing both sides Show more…
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